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Post by dad2paisley on Apr 19, 2016 10:42:11 GMT -5
Suppose you're in a hallway lined with 100 closed lockers. You begin by opening every locker. Then you close every second locker. Then you go to every third locker and open it (if it's closed) or close it (if it's open). Let's call this action toggling a locker. Continue toggling every nth locker on pass number n. After 100 passes, where you toggle only locker #100, how many lockers are open?
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Post by greydaddy on Apr 20, 2016 9:59:45 GMT -5
hmm... let me see if I can do this.
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Post by greydaddy on Apr 20, 2016 10:39:15 GMT -5
I don't know.
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Post by dad2paisley on Apr 20, 2016 10:40:03 GMT -5
Answer: 10 lockers are left open: Lockers #1, 4, 9, 16, 25, 36, 49, 64, 81, and 100. Each of these numbers are perfect squares. This problem is based on the factors of the locker number. Each locker is toggled by each factor; for example, locker #40 is toggled on pass number 1, 2, 4, 5, 8, 10, 20, and 40. That's eight toggles: open-closed-open-closed-open-closed-open-closed.
The only way a locker could be left open is if it is toggled an odd number of times. The only numbers with an odd number of factors are the perfect squares. Thus, the perfect squares are left open.
For example, locker #25 is toggled on pass number 1, 5, and 25 (three toggles): open-closed-open.
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Post by mom2remy on Apr 25, 2016 12:39:19 GMT -5
That was hard.
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